Matematika Sekolah Menengah Pertama 2. Perhatikan gambar berikut! G C H E F 8 cm DI C 6 cm B А 15 cm Hitunglah luas permukaan balok tersebut!​

2. Perhatikan gambar berikut! G C H E F 8 cm DI C 6 cm B А 15 cm Hitunglah luas permukaan balok tersebut!​

[tex] \mathbb \color{aqua} \underbrace{JAWABAN}[/tex]

516 cm²

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[tex] \mathbb \color{gold} \underbrace{RUMUS}[/tex]

[tex] \mathbb \color{gold} \underbrace{RUMUS}[/tex]

=> Volume Balok :

[tex] \boxed{ \sf V = p \times l \times t} \\ [/tex]

=> Luas Permukaan Balok :

[tex] \boxed{ \sf L = 2(pl + pt + lt)}[/tex]

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[tex] \mathbb \color{orange} \underbrace{PENYELESAIAN}[/tex]

[tex] \underline{ \overline{ \boxed{ \bold{diketahui}}}}[/tex]

  • Panjang (p) = 15 cm
  • Lebar (l) = 6 cm
  • Tinggi (t) = 8 cm

[tex] \\ \underline{ \overline{ \boxed{ \bold{ditanya}}}}[/tex]

  • Luas Permukaan Balok

[tex] \\ \underline{ \overline{ \boxed{ \bold{jawab}}}}[/tex]

[tex] \begin{aligned} \sf L &= \sf 2(pl + pt + lt) \\ \sf L &= \sf 2((15 \times 6) + (15 \times 8) + (6 \times 8)) \\ \sf L &= \sf 2(90 + 120 + 48) \\ \sf L &= \sf 2(258) \\ \sf L &= \bold{516 \: {cm}^{2} } \end{aligned}[/tex]

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[tex] \mathbb \color{red} \underbrace{KESIMPULAN}[/tex]

Jadi, luas permukaan balok tersebut adalah 516 cm²

[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} [/tex]

Jawaban:

Rumus luas permukaan balok :

2 × ( PL + PT + LT )

Jawaban :

2 × P × L = 2 × 15 × 6 = 180

2 × P × T = 2 × 15 × 8 = 240

2 × L × T = 2 × 6 × 8 = 96

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516 cm

Jadi luas permukaannya adalah 516 cm

Maaf bila ada kesalahan pada jawaban

Semoga membantu

Have a nice day

Semangat belajar !

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