Matematika Sekolah Dasar Q. special tahun baru

[tex] {10}^{2} + {50}^{2} = [/tex]
[tex] \sqrt{100} = [/tex]
[tex] \sqrt{81} = [/tex]
[tex] \frac{2}{8} + \frac{3}{8} = [/tex]
[tex] {80}^{4} = [/tex]
[tex]selamat \: mengerjakan[/tex]
[tex]happy \: new \: year \: [/tex]

Q. special tahun baru

[tex] {10}^{2} + {50}^{2} = [/tex]
[tex] \sqrt{100} = [/tex]
[tex] \sqrt{81} = [/tex]
[tex] \frac{2}{8} + \frac{3}{8} = [/tex]
[tex] {80}^{4} = [/tex]
[tex]selamat \: mengerjakan[/tex]
[tex]happy \: new \: year \: [/tex]

[tex]\tt {10}^{2} + {50}^{2} [/tex]

= ( 10 × 10 ) + ( 50 × 50 )

= 100 + 650

= 850

_______________________

[tex] \tt \sqrt{100} [/tex]

[tex] \tt = \sqrt{ {10}^{2} } [/tex]

[tex] \tt = \sqrt{10 \times 10} [/tex]

[tex] \tt = 10[/tex]

________________________

[tex] \tt \sqrt{81} [/tex]

[tex] \tt = \sqrt{ {9}^{2} } [/tex]

[tex] \tt = \sqrt{9 \times 9} [/tex]

[tex] \tt = 9[/tex]

________________________

2/8 + 3/8

= ( 3 + 2 )/8

= 5/8

________________________

[tex] {80}^{4} [/tex]

= 80 × 80 × 80 × 80

= 6.400 × 6.400

= 40.960.000

Jawab:

10² + 50² = 2.600

√100 = 10

√81 = 9

[tex]\frac{2}{8} + \frac{3}{8} \\[/tex] [tex]= \frac{5}{8}[/tex]

80⁴ = 40.960.000

Penjelasan dengan langkah-langkah:

10² + 50²

= (10 x 10) + (50 x 50)

= 100 + 2.500

= 2.600

_______

√100

= √10²

= √10 x 10

= 10

_______

√81

= √9²

= √9 x 9

= 9

_______

[tex]\frac{2}{8} + \frac{3}{8} \\[/tex]

[tex]= \frac{2+3}{8}[/tex]

[tex]= \frac{5}{8}[/tex]

_______

80⁴

= 80 × 80 × 80 × 80

= 6.400 x 6.400

= 40.960.000

atau dengan cara

= 80 × 80 × 80 × 80

= 6.400 x 80 x 80

= 512.000 x 80

= 40.960.000

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